8f0325c05b
Could have implemented this check (if menu is showing) inside the show() method of BrowserMenu but this would mean the client (us) would go to the process of building a new menu and then trying to have it displayed only for this to be ignored by BrowserMenu in a somewhat opaque way. Having this check done as soon as possible offers us full control and avoids the unnecessary steps for building an already shown menu. |
||
---|---|---|
.. | ||
androidTest | ||
debug | ||
fenixBeta/res/xml | ||
fenixNightly | ||
fennecProduction | ||
geckoBeta/java/org/mozilla/fenix/engine | ||
geckoNightly/java/org/mozilla/fenix/engine | ||
main | ||
test |